Today we started a new unit on linear programming. The big idea of this unit is to use graphs and technology to solve problems involving inequality relationships, always having to find the best solution for each problem.
Here is the example that we did in class:
A zoo is given a sum of money to spend on monkeys and rabbits. The zoo must spend at least $2000 on the purchase to qualify for the grant. At least 14 animals must be bought. Each rabbit costs $40.00 and each monkey costs $400.00.
c) What is the best way the zoo can spend the money?
d) Suppose that it costs $1.00 per day to feed a rabbit and $5.00 per day to feed a monkey. Write the cost equation. How much will it cost to feed all the rabbits and monkeys they purchase?
40x+400y>=2000 Therefore the answer is 4 monkeys and 10 rabbits
40(10)+400(4)=2000
5(4)+1(10)=30 Therefore the answer is $30 to feed the monkeys and rabbits.
We verified on graphmatica that our answer was correct because it was the most critical point.
This unit is mostly going to be solving problems with skills that we may already know, but just improving on them.
To find the absolute value on your calculator, you press 2nd, then zero, and it is the first one on there-abs.
In graphmatica you just type in abs and put the letter or number in brackets.
On tuesdays Mr. Max is here until 4:30 for extra help if needed!
The objectives that have to be mastered are 32-45ish.
